Solve definite and indefinite integrals with detailed step-by-step working. Supports polynomial expressions, power rule integration, and area under curve calculations.
Find the area under f(x) = x² from x = 0 to x = 3.
Indefinite integral: ∫ x² dx = x³/3 + C
Definite integral: ∫₀³ x² dx = [x³/3]₀³ = 27/3 − 0 = 9 square units
The area bounded by the parabola y = x², the x-axis, and the lines x = 0 and x = 3 is 9 units².
A particle moves with velocity v(t) = 2t + 3 m/s. Find the distance traveled from t = 1 to t = 5.
Indefinite integral: ∫ (2t + 3) dt = t² + 3t + C
Definite integral: ∫₁⁵ (2t + 3) dt = [t² + 3t]₁⁵ = (25 + 15) − (1 + 3) = 36 meters
The integral of velocity gives displacement. The particle travels 36 meters between t = 1 and t = 5 seconds.
Find the indefinite integral of f(x) = 4x³ + 3x² + 2x + 5
Integration: ∫ (4x³ + 3x² + 2x + 5) dx
Step 1: 4x³ → 4 · x⁴/4 = x⁴
Step 2: 3x² → 3 · x³/3 = x³
Step 3: 2x → 2 · x²/2 = x²
Step 4: 5 → 5x
Result: x⁴ + x³ + x² + 5x + C
Find the area between f(x) = x² and the x-axis from x = −2 to x = 2.
∫ x² dx from −2 to 2
Antiderivative: x³/3
Evaluate: [x³/3]₋₂² = (8/3) − (−8/3) = 16/3 ≈ 5.333 square units
Since x² is symmetric and always positive, the area is twice the area from 0 to 2.
An integral is a mathematical operation that finds the area under a curve (definite integral) or the antiderivative of a function (indefinite integral). Integration is the inverse operation of differentiation.
You can verify your integration by differentiating the result. If you get back the original function, the integration is correct.
The power rule fails when n = −1 (i.e., 1/x). In that case, the integral is ln|x| + C, not x⁰/0.
Indefinite integrals always include the constant of integration +C because the derivative of any constant is zero.
Definite integrals give signed area. Area below the x-axis is negative. For total area, take the absolute value or split the integral at roots.
An integral is a fundamental concept in calculus that represents the accumulation of quantities, such as areas under curves, total displacement from velocity, or the antiderivative of a function. Integration is the inverse operation of differentiation — together they form the core of calculus.
There are two main types of integrals: indefinite integrals (antiderivatives) which give a family of functions differing by a constant, and definite integrals which compute the signed area under a curve between two specific points. The definite integral is defined by the Fundamental Theorem of Calculus, which connects differentiation and integration.
For polynomial functions, integration follows the power rule: ∫ xn dx = xn+1/(n+1) + C (for n ≠ −1). Each term is integrated separately, and the results are combined. The constant of integration +C is added for indefinite integrals, representing any constant value whose derivative would be zero.
Integrating a polynomial is straightforward using the power rule and the linearity of integration. The integral of a sum is the sum of the integrals, and constant factors can be pulled out. Here's how it works:
Example: Integrate f(x) = 3x² + 2x + 1
Step 1: Separate into terms. The polynomial has three terms: 3x², 2x, and 1.
Step 2: Integrate each term using the power rule:
∫ 3x² dx = 3 · x³/3 = x³
∫ 2x dx = 2 · x²/2 = x²
∫ 1 dx = x (since 1 = x⁰ and x⁰⁺¹/(0+1) = x)
Step 3: Combine the results: x³ + x² + x + C
For a definite integral, evaluate the antiderivative at the upper bound and subtract the value at the lower bound. For example, ∫₀² (3x² + 2x + 1) dx = [x³ + x² + x]₀² = (8 + 4 + 2) − (0) = 14.
The key difference between definite and indefinite integrals is that indefinite integrals produce a family of functions (antiderivatives) plus a constant of integration, while definite integrals produce a specific numerical value representing the signed area under the curve.
Written as ∫ f(x) dx = F(x) + C. Results in a function. Used to find antiderivatives and solve differential equations. Always includes +C.
Written as ∫ₐᵇ f(x) dx = F(b) − F(a). Results in a number. Used to compute areas, volumes, total change, and accumulated quantities.
The Fundamental Theorem of Calculus connects them: the definite integral of f from a to b equals F(b) − F(a), where F is any antiderivative of f.
For functions that are difficult to integrate analytically, numerical methods like the trapezoidal rule or Simpson's rule can approximate definite integrals.
⚠️ Important Note: This Integral Calculator is designed for educational and informational purposes. It handles polynomial integration using the power rule. While every effort has been made to ensure accuracy, results should be verified independently for critical applications such as engineering, physics, or financial decisions involving integration. Always consult a qualified professional for calculus-related decisions in high-stakes contexts.